2/3(x)^2+7/3(x)=5

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Solution for 2/3(x)^2+7/3(x)=5 equation: 


x in (-oo:+oo)

(2/3)*x^2+(7/3)*x = 5 // - 5

(2/3)*x^2+(7/3)*x-5 = 0

2/3*x^2+7/3*x-5 = 0

DELTA = (7/3)^2-(-5*2/3*4)

DELTA = 169/9

DELTA > 0

x = ((169/9)^(1/2)-7/3)/(2/3*2) or x = (-(169/9)^(1/2)-7/3)/(2/3*2)

x = 3/2 or x = -5

x in { -5, 3/2 }

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